[Year 12 SofDev] Help needed

[Esther Andrews]

You are right, it never passes to the second loop. And is the TOTAL for the green and red colors combined or do you need two different totals?

But perhaps something like this is what you were after:

BEGIN

SET TOTALGREEN TO 0

SET TOTALRED TO 0

SET COUNTER TO 1

WHILE COUNTER < 4

TOTALGREEN = TOTALGREEN + COLOUR [COUNTER] . GREENVALUE

TOTALRED = TOTALRED + COLOUR [COUNTER] . REDVALUE

ADD 1 TO COUNTER

ENDWHILE

PRINT TOTALGREEN, TOTALRED

END


From: sofdev-bounces at edulists.com.au [mailto:sofdev-bounces at edulists.com.au] On Behalf Of Brett Groves
Sent: Wednesday, 25 May 2011 11:43 AM
To: Year 12 Software Development Teachers' Mailing List
Subject: [Year 12 SofDev] Help needed

Hi all,

Wondering if some kind soul who is good with desk checks / pseudo code can help me out here. We are about to commence OC2 (running a week late) and I have given my students some algorithms to evaluate for revision. On one in particular I realised I made an error of logic when evaluatiing it myself and have now confused my self to point of frustration. It's the one below. It has two count loops which it uses to select data in an array but they both have identical conditions. As I am currently reading it values will never be passed to the second loop as the evaluation condition that ends the first loop will also end the second???? Scratches head......sure I'm failing to see obvious! Can anyone help pls

Brett

Question 12:

The following diagram shows the contents of an array of records used for mixing colours.

The name of the array is 'COLOUR'.
The algorithm below is used to calculate colour values, using an array.

BEGIN

SET TOTAL TO 0

SET COUNTER TO 1

WHILE COUNTER < 4

TOTAL = TOTAL + COLOUR [COUNTER] . GREENVALUE

ADD 1 TO COUNTER

ENDWHILE

WHILE COUNTER < 4

TOTAL = TOTAL + COLOUR [COUNTER] . REDVALUE

ADD 1 TO COUNTER

ENDWHILE

PRINT TOTAL

END



What will be the output of this algorithm?

(A) 10

(B) 11

(C) 18

(D) 25


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